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PHYSICS

Sunday, July 20, 2008
Asked by: AMOL
Subject: PHYSICS
Question: WHAT IS MISTRY BEHIND BLACK HOLE?
AND HOW CAN CALCULATE ITS GRAVITY?
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posted by S @ 7:50 PM  
2 Comments :
  • At July 20, 2008 at 10:27 PM, Anonymous Physicskerala said…

    When the radius of the stars become denser and denser the attractive force increases.......

    no photon can ever leave the star

    Schwarzschild radius
    Rs = {(2GM)/c*c}

     
  • At August 14, 2008 at 9:50 PM, Anonymous z.zain said…

    if a star whose mass is atleast 10-15 times the solar mass ,undergoes supernova explosion,then it will leave a massive remnant.by now all the nuclear fuel is exhausted and nuclear reactions are stoped,therefore there is no outward force to oppose gravitational force and as a result the stellar remnant will collapse on itself i.e. contaction starts and a stage is reached when it becomes a point of zero volume and infinte density,because of infinite density no light escapes because emitted photons are trapped in to a orbit by intense gravitational field &there4appears black. as nothing can escape from black hole therefore escape velocity is infinite and from the formula of escape velocity we can conclude that gravity is also infinite.

     

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