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Work done in moving a particle in a force field

Friday, September 19, 2008
The work done in moving a particle in the force field F = 5x^2 i +
(xz-y) j + 3z k
alog the straight line joining (0,0,0) to (1,1,1) is ------

Explain how it is calculated.

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posted by S @ 12:28 PM  
1 Comments :
  • At November 15, 2009 at 10:11 PM, Anonymous Anonymous said…

    Here initial position is origon i.e having position vector 0i^+0j^+0k^and final position is 1i^+1j^+1K^,
    Now find displacement vector by subtracting the former from later and then take dot product with force vector F.

     

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